Simple maths question.

retired_lyriclemelodee · 11-05-2007, 11:04 PM

If something has gone from 48 to 70 how do I find the percentage increase, and what is the formula?

Must have done this so many times at college, but completely forgotten the formula.

Thanks.

retired_acivin · 11-05-2007, 11:04 PM

(78-40)/40
This is the percentage increase.

(Final value - Initial Value)/Initial Value

retired_mygem19 · 11-05-2007, 11:05 PM

divide by x and add the integer before multiplying by y and adding g, q, z and j.

Duh

retired_kpr · 11-05-2007, 11:06 PM

Quote:

Originally posted by atvkwkad:
divide by x and add the integer before multiplying by y and adding g, q, z and j.

Duh

like it :thup:

retired_charlene · 11-05-2007, 11:07 PM

what atvkwkad said, just you have to find the complex conjugate of that and then you're done

buffdaddy110 · 11-05-2007, 11:08 PM

Quote:

Originally posted by prince_capri:
<STRIKE>(78-40)/40</STRIKE>
This is the percentage increase.

(Final value - Initial Value)/Initial Value

(70-48)/48

retired_nini59 · 11-05-2007, 11:10 PM

to be exact it's (70-48)/48*100%

retired_jjjvassnc · 11-05-2007, 11:15 PM

Yeah, wts :thup:

retired_acivin · 11-05-2007, 11:19 PM

Quote:

Originally posted by Half-time Orange:
<BLOCKQUOTE>Originally posted by prince_capri:
<STRIKE>(78-40)/40</STRIKE>
This is the percentage increase.

(Final value - Initial Value)/Initial Value

(70-48)/48 </BLOCKQUOTE>

No wonder I always used to get penalized for copying wrong!